1.	(a)	(i)	Kilograms	2
B1 for kg
(ii)	Metres
B1 for m
(b)	(i)	30	2
B1 for 30
(ii)	4000
B1 for 4000
[4]

2.	Offer £198240 so she will NOT accept.	6
	Area of CP =  oe = 840 + 6240 = 7080
She will accept more than 28 × “7080” = 198240 so She will NOT accept.
M1 for suitable split and attempt to find full area
A2 for both (unsimplified) sectional areas correct
(A1 for one (unsimplified) sectional area correct)
A1 for 7080 (can be awarded if 198 240 seen)
M1(dep on prev. M1) for 28 × “7080”
A1 for both 198240 and She will NOT accept.
[6]

3.	(a)	3(x+2)	1
B1 for 3(x+2)
(b)	12x + 24 oe	2
	3x + 6 + 4x +8+5x + 10
M1 for adding the three lengths
A1 for 12x + 24 oe
(c)	(i)	1.5	4
	12x+24 = 42
M1 for forming the equation “12x+24” = 42
A1 for 1.5 oe
(ii)	10.5
	3x + 6 = 3 × “1.5” + 6
M1 for 3 × “1.5” + 6
A1ft (ft on cand’s value for x)
[7]

4.	9 sides	2
	 = 9
M1 for 
A1 cao
[2]

5.	(a)	3390 cm2	3
	CSA= 2 ×π × 54 × 10 (=3392.92…)
M1 for 2 ×π × 54 × 10
A1 for 3390 or better
B1 for cm2
(b)	printed result shown	4
	x2 =  (=11705)
x = 
	= 108.1896…
	> diameter (108) of the circular top (so triangle cannot fit on top of
cylinder without overlapping)
M1 for  ( or 11705 seen)
M1(dep) for 
A1 for 108.1(896…)
A1 for convincing conclusion
[7]

6.	explanation	1
B1 mentions 87.5 + 64.5 or 0.5 out each etc
[1]

7.	75 cm2	4
	2p × 10 ×  = 15
x = 
A = p × 102 × 
M1 for p × 102 (= 314¼) or 2 × p × 10 (= 62.8¼)
M1 for  (= 4.18)
M1 for 
A1 for 74.9 £ ans £ 75.1
Alternative method
M1 for p × 102 (= 314.1¼) or 2 × p × 10 (= 62.8¼)
M1 for (= 0.238¼)
M1 for p × r2 × “0.238”
A1 for 74.9 £ ans £ 75.1
Alternative method
M1 for p × 102 (= 314.1¼) or 2 × p × 10 (= 62.8¼)
M1 for (= 85.9)
M1 for  ×p × r2
A1 for 74.9 £ ans £ 75.1
[4]

8.	(a)		2
	Angle ABE = angle CDE (alternate angles)
Angle BAE = angle DCE (alternate angles)
Angle AEB = angle CED (vertically opposite angles)
So triangles ABE and CDE are similar
B2 for full explanation
(B1 for one statement with reason)

(b)		3

M1 for 
A1 for 
A1 for 
[5]

9.	48	2
	
B2 for an answer in the range of 44 to 52
(B1 for a factor of or  oe seen)
[2]

10.	(i)	6	3
B1 for 6
(ii)	8
B1 for 8
(iii)	12
B1 for 12
[3]

11.	(a)	(i)	6.75	1
B1 cao
(ii)	6.65	1
B1 cao
(b)	(i)	26.95 ÷ 6.65
4.05263	3
M1 for “26.95” ÷ “6.65” where 26.9 < “26.95” £ 26.95 and
6.65 ≤ “6.65” < 6.7
A1 for 4.05263 (....)

(ii)	26.85 ÷ 6.75
3.97778
If M1 not earned in (i), then M1 for ‘26.85’÷’6.75’ where 26.85 ≤ ‘26.85’ < 26.9 and 6.7 < ‘6.75’ £ 6.75
A1 for 3.9777 (.....)
(c)	(i)	4	2
B1 cao
(ii)	bounds agree to 1sf
B1 for appropriate reason for 4
[7]

12.	113.…	3
	p(6)2
M1 p(6)2
A1 113.…
B1 (indep) cm2
[3]

13.	42 + 62 
16 + 36 = 52

7.21	3
M1 for 42 + 62 or 16 + 36 or 52
M1 for  + 36 or 
A1 for 7.21 – 7.212
[3]

14.	(a)	(i)	6.75	1
B1 cao
(ii)	6.65	1
B1 cao
(b)	(i)	26.95 ÷ 6.65
4.05263	3
M1 for “26.95” ÷ “6.65” where 26.9 < “26.95” ≤ 26.95 and 6.65 ≤ “6.65” < 6.7
A1 for 4.05263 (....)
If M1 not earned in (i), then M1 for “26.85” ÷ ”6.75” where 26.85 ≤ “26.85” < 26.9 and 6.7 < “6.75” ≤ 6.75
(ii)	26.85 ÷ 6.75
3.97778
A1 for 3.9777 (.....)

(c)	bounds agree to 1sf
4	1
B1 cao
[6]

15.	(a)	14	1
B1 cao
(b)	6	1
B1 cao
(c)	Correct reflection	2
B2 fully correct
(B1 correct reflection in a line parallel to the mirror line or condoning 1 block error in shape or position of shape)
[4]

16.	40	1
B1
[1]

17.		2
	Barry (8) because you double
Kath (7) because you add, 1,2,3
B1 oe
B1 oe
SC: B1 for correct rules only
[2]

18.	(a)	37.7cm	2
	p ´ 12
M1 for p ´ 12
A1 for 37.68 – 37.71
(b)	200cm2	2
	0.5 ´ 10 ´ 10 = 50
50 ´ 4 = 200
M1 for 0.5 × 10 × 10, 0.5 × 10 × 20, 0.5 × 20 × 20, √(102 + 102), or 5 seen
A1 cao for 200
[4]

19.	£75.30	5
	3.2 ´ 2.8 = 8.96
2 ´ 4.5 ´ 2.8 = 25.2
2 ´ 4.5 ´ 28.8 = 28.8

M1 for area of any face found correctly
M1 for 2 areas found correctly
A1 for 62.96 or 54
M1 for 
Al cao
Alternate method for candidates who round up 
M1 for “26” ´ 2.99
A1 for £77.74 cao
SC: for top included B2 for 71.92 m2 seen or
B3 for £86.02 seen
SC B4 for £64.58 or £65.78 seen
[5]

20.	Area = 0.5 × (2 + 6) × 3
= 0.5 × 8 ×3
= 12 m2	3
M1 for 0.5 × (2 + 6) × 3 oe
A1 for 12
B1 for m2
[3]

21.	(a)	Trapezium	1
B1 cao ignore spelling
(b)	(2, 3)	1
B1 cao
(c)	Isosceles	1
B1 cao ignore spelling
(d)	Q correct	1
B1 cao
[4]

22.	(a)	x + 2	1
B1 accept 2 + x but not x = x + 2

(b)	4x + 14	2
	
	x + 5 + x + 5 +x + 2 + x +2
M1 adding 4 sides, two of which are ‘x + 2’ (all sides to be linear expressions in x)
SC x + 5 + x + 2 ´ 2 gets M1
A1 for correct simplified answer or (20 – 14) ¸ 4 oe gets M1
(c)	1.5 oe	2
	‘4x + 14’ = 20
M1 for equation
A1 cao
[5]

23.	(a)		1
B1 cao
(b)		1
	1 + 2 + 3 + 4 + 5 + 6 + 7 + 8
B1 cao
(c)	5050	1
	
B1 cao
[3]

24.	21.8	3
	tan P = 5 – 12.5
M1 for correct use of tan P = 5 – 12.5 (accept tan 5 – 12.5)
M1 for tan-1 oe, condone tan-1 5 – 12.5
A1 21.8 – 21.81
NB 6.29 – 6.3 gets M2 A0 by implication
[3]

25.	287	3
	138 – 65 = 73
360 – 73
M1 180 – 138 = 42°, 107° seen
M1 180 – (65+”42”) = 73° seen
A1 for 287° cao
[3]

26.	(a)	Diagram	1
B1 cao
(b)	22, 26	1
B1 cao
(c)	46	1
B1 cao
[3]

27.	(a)	10	1
B1 cao
(b)	5.5	1
B1 ±0.3 pounds
(c)	50	3
	
M1 for use of graph at 11 or 
A1 for 5
A1 cao
SC B2 for 49.5 – 50.6
[5]

28.	(a)	90	2
B2 for 90 ± 2 (B1 for 9 ± 0.2)
(b)	317	1
B1 for 317 ± 4
[3]

29.	(a)	60	1
B1 cao
(b)	120	2
	360 - 60 - 90 - 90
M1 for 360 - “ 60 ” - 90 - 90 or 180 – “60”
A1 cao
(c)	12	2
	6 ´ 2
M1 for 6 ´ 2
A1 cao for 12
[5]

30.	170	4
	Vol = π × 3.82 × 2.5 = π × 14.44 × 2.5
= 45.36… × 2.5 = 113.411
Mass = “113” × 1.5 = 170.1165
M1 for π × r2 × 2.5 where r = is 3.8 or 7.6
A1 if r = 3.8
M1 for “113” × 1.5
A1 for 169.5 – 170.3 cao
[4]

31.	88.4cm2	3
	
M1 for 
A1 88.3 - 88.4
B1 for cm²(independent)
[3]

32.	(0) 9 25	3
	87 ÷ 36 = 2.41666…
0. 41666… × 60 = 25
or
2.41666…× 60 = 145
M1 for 87 ÷ 36 or 2.41(666)…or 2.42 seen
M1 ft for “2.41666…” × 60 oe, or 0.41666…× 60
A1 cao
SC. B1 for 2 hour 41 minutes or 2 hrs 42 mins or 942 or 941
[3]

33.	(a)	8	2
	SF = 

M1 for sight of  or or 1.67 or better or 
A1 cao

(b)	19.8	2
	
M1 for use of SF from (a) to find AC or BC or
and adding 4 sides
A1 cao
[4]

34.	754 cm3	3
	π n × 42 × 15 = 753.6
M1 for π × 42 × 15
A1 for 753.6 to 754.1
B1 (indep) for cm3
[3]

35.	(a)	31°	2
	62 ¸ 2
M1 for 62 ÷ 2 or 118° seen
A1 cao
(b)	135°	3
	360 ÷ 8 = 45	or	6 × 180 = 1080
	180 – 45 = 135	1080 ÷ 8 = 135
M1 for 360 ÷ 8 (= 45) or 6 × 180(= 1080)
M1 for 180 – 45 or 1080 ÷ 8
A1 cao
[5]